Basic Examples (3)
Compute the distribution of the amount in excess of 2/3 for a uniform distribution on the interval from 0 to 1:
Compute the mean of the excess:
Compute the distribution of the amount in excess of a point for a uniform distribution in four dimensions:
Compute the mean of the excess:
Compute the distribution of the amount in excess of 10 for a log-normal distribution with a mean of 9 and a median of 3:
Compute the mean and standard deviation:
Scope (2)
The function works with discrete distributions:
One can compute a symbolic non-negative excess distribution from an underlying symbolic univariate distribution:
Compute various statistics of the resulting distribution:
Calculate for a numeric value:
Properties and Relations (2)
One can nest non-negative excess distributions. Compute the mean amount owed by an insured who has a primary policy that covers up to 2/3 and a secondary policy that will pay any amount remaining (but not exceeding 1/10) after the primary has paid its 2/3:
The result is no different than if there was a primary policy with a limit of 2/3 and 1/10:
Applications (2)
An excess insurer agrees to pay for damages in excess of $250,000 suffered by an insured where the distribution of losses is logarithmic, the mean loss is $10,000, and the median loss is $2,800. What premium would cause the excess insurer to break even:
A reinsurer agrees to pay 80% of the excess insurer's loss that is in turn over $100,000. What premium would cause the reinsurer to break even:
Possible Issues (2)
A mismatch between the dimension of value and the dimension of the distribution dist will gives an invalid distribution:
When one attempts to work with the resulting distribution errors can occur:
Neat Examples (6)
Consider a distribution of judgments in a lawsuit that may be modeled as a log-normal distribution:
Imagine an insurance policy with a limit of 20 and consider the expected positions of the insurer and insured:
Now, consider a second distribution with the same mean but a higher median:
Examine the positions of the insurer and the insured:
Note the conflict in perspectives. From the perspective of the insurer, the second distribution leaves them in a worse expected position. From the perspective of the insured, the second distribution leaves them in a better position. Plot the difference in case values as the median goes from 1 to 9.9:
Consider how risk aversion alters the analysis. Suppose that when the insured considers two outputs from a distribution, they focus on the worst case: