returns in output the variables we have to integrate over to compute the value of this diagram. In this case we will have a three-dimensional integral to perform.
In[4]:=
MomVars
@integrand4229
Out[4]=
{
[1]
ρ
,
[2]
θ
,
[2]
ρ
}
Let's look at the case with the triangle subdiagram substituted
In[5]:=
VisualizeDiagram
[4,2,2,9,"Substitutions""Analytics"],
IntegrandDiagram
[4,2,2,9,"Substitutions""Analytics"]
Out[5]=
,2
2
[[1]]
[-[1],[1],0]
In[6]:=
integrand4229triangle=
WriteExplicit
@
IntegrandDiagram
[4,2,2,9,"Substitutions""Analytics"]
Out[6]=
1
4π
2
1+
2
[1]
ρ
4+
2
[1]
ρ
The integral to perform is just one-dimensional. Notice how the