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Wolfram Language
GERF
Symbols
GERFSolve
Taggar`GERF`
G
E
R
F
S
o
l
v
e
G
E
R
F
S
o
l
v
e
[
l
h
s
=
r
h
s
,
u
[
v
a
r
s
]
,
.
.
.
]
s
o
l
v
e
s
t
h
e
N
L
P
D
E
g
i
v
e
n
b
y
l
h
s
=
r
h
s
f
o
r
u
[
v
a
r
s
]
u
s
i
n
g
t
h
e
G
E
R
F
m
e
t
h
o
d
.
D
e
t
a
i
l
s
a
n
d
O
p
t
i
o
n
s
Examples
(
7
)
Basic Examples
(
3
)
This is the Burgers' equation in
(
1
+
1
)
-dimensions:
I
n
[
1
]
:
=
b
u
r
g
e
r
s
=
∂
t
u
[
x
,
t
]
+
u
[
x
,
t
]
∂
x
u
[
x
,
t
]
-
ν
∂
x
,
x
u
[
x
,
t
]
0
O
u
t
[
1
]
=
(
0
,
1
)
u
[
x
,
t
]
+
u
[
x
,
t
]
(
1
,
0
)
u
[
x
,
t
]
-
ν
(
2
,
0
)
u
[
x
,
t
]
0
Solve it using GERF method:
I
n
[
2
]
:
=
G
E
R
F
S
o
l
v
e
[
b
u
r
g
e
r
s
,
u
[
x
,
t
]
]
O
u
t
[
2
]
=
u
[
x
,
t
]
0
,
u
[
x
,
t
]
0
+
(
-
x
1
-
t
0
1
+
x
1
-
t
0
1
)
1
-
-
x
1
-
t
0
1
+
x
1
-
t
0
1
,
u
[
x
,
t
]
(
-
-
x
1
-
t
0
1
+
x
1
-
t
0
1
)
-
1
-
x
1
-
t
0
1
+
x
1
-
t
0
1
+
0
,
u
[
x
,
t
]
(
-
-
x
1
-
t
0
1
+
x
1
-
t
0
1
)
-
1
-
x
1
-
t
0
1
+
x
1
-
t
0
1
+
(
-
x
1
-
t
0
1
+
x
1
-
t
0
1
)
-
1
-
-
x
1
-
t
0
1
+
x
1
-
t
0
1
+
0
Obtain the solution sets as well:
I
n
[
3
]
:
=
s
o
l
s
=
G
E
R
F
S
o
l
v
e
[
b
u
r
g
e
r
s
,
u
[
x
,
t
]
,
"
O
u
t
p
u
t
M
o
d
e
"
"
B
o
t
h
"
]
O
u
t
[
3
]
=
{
{
-
1
0
,
1
0
}
,
u
[
x
,
t
]
0
}
,
ν
1
2
1
,
-
1
0
,
2
-
0
1
,
u
[
x
,
t
]
0
+
(
-
x
1
-
t
0
1
+
x
1
-
t
0
1
)
1
-
-
x
1
-
t
0
1
+
x
1
-
t
0
1
,
ν
-
1
2
1
,
1
0
,
2
-
0
1
,
u
[
x
,
t
]
(
-
-
x
1
-
t
0
1
+
x
1
-
t
0
1
)
-
1
-
x
1
-
t
0
1
+
x
1
-
t
0
1
+
0
,
ν
-
1
2
1
,
1
-
1
,
2
-
0
1
,
u
[
x
,
t
]
(
-
-
x
1
-
t
0
1
+
x
1
-
t
0
1
)
-
1
-
x
1
-
t
0
1
+
x
1
-
t
0
1
+
(
-
x
1
-
t
0
1
+
x
1
-
t
0
1
)
-
1
-
-
x
1
-
t
0
1
+
x
1
-
t
0
1
+
0
Verify that the solutions are valid:
I
n
[
4
]
:
=
p
i
c
k
=
s
o
l
s
〚
2
〛
;
b
u
r
g
e
r
s
/
.
u
F
u
n
c
t
i
o
n
[
{
x
,
t
}
,
p
i
c
k
〚
2
,
2
〛
]
O
u
t
[
4
]
=
T
r
u
e
Another example, Calogero–Bogoyavlenskii–Schiff equation in
(
2
+
1
)
-dimensions:
I
n
[
1
]
:
=
c
b
s
=
∂
x
,
t
u
[
x
,
y
,
t
]
+
4
∂
x
u
[
x
,
y
,
t
]
∂
x
,
y
u
[
x
,
y
,
t
]
+
2
∂
x
,
x
u
[
x
,
y
,
t
]
∂
y
u
[
x
,
y
,
t
]
+
∂
x
,
x
,
x
,
y
u
[
x
,
y
,
t
]
0
;
Solve it:
I
n
[
2
]
:
=
s
o
l
s
=
G
E
R
F
S
o
l
v
e
[
c
b
s
,
u
[
x
,
y
,
t
]
]
O
u
t
[
2
]
=
u
[
x
,
y
,
t
]
(
-
-
y
2
+
t
3
+
y
2
+
t
3
)
-
1
-
y
2
+
t
3
+
y
2
+
t
3
+
0
+
(
-
y
2
+
t
3
+
y
2
+
t
3
)
1
-
-
y
2
+
t
3
+
y
2
+
t
3
,
u
[
x
,
y
,
t
]
0
,
u
[
x
,
y
,
t
]
(
-
-
y
2
+
y
2
)
-
1
-
y
2
+
y
2
+
0
+
(
-
y
2
+
y
2
)
1
-
-
y
2
+
y
2
,
u
[
x
,
y
,
t
]
(
-
-
x
1
+
x
1
)
-
1
-
x
1
+
x
1
+
0
+
(
-
x
1
+
x
1
)
1
-
-
x
1
+
x
1
,
u
[
x
,
y
,
t
]
0
+
2
-
x
1
+
y
2
+
4
t
2
1
2
+
x
1
+
y
2
+
4
t
2
1
2
1
-
-
x
1
+
y
2
+
4
t
2
1
2
+
x
1
+
y
2
+
4
t
2
1
2
,
u
[
x
,
y
,
t
]
0
+
2
-
-
x
1
+
y
2
+
4
t
2
1
2
+
x
1
+
y
2
+
4
t
2
1
2
1
-
x
1
+
y
2
+
4
t
2
1
2
+
x
1
+
y
2
+
4
t
2
1
2
,
u
[
x
,
y
,
t
]
0
+
2
-
-
x
1
+
y
2
+
1
6
t
2
1
2
+
x
1
+
y
2
+
1
6
t
2
1
2
1
-
x
1
+
y
2
+
1
6
t
2
1
2
+
x
1
+
y
2
+
1
6
t
2
1
2
+
2
-
x
1
+
y
2
+
1
6
t
2
1
2
+
x
1
+
y
2
+
1
6
t
2
1
2
1
-
-
x
1
+
y
2
+
1
6
t
2
1
2
+
x
1
+
y
2
+
1
6
t
2
1
2
,
u
[
x
,
y
,
t
]
(
-
-
y
2
+
y
2
)
-
1
-
y
2
+
y
2
+
(
-
y
2
+
y
2
)
-
1
-
-
y
2
+
y
2
+
0
,
u
[
x
,
y
,
t
]
(
-
-
x
1
+
x
1
)
-
1
-
x
1
+
x
1
+
(
-
x
1
+
x
1
)
-
1
-
-
x
1
+
x
1
+
0
Verification:
I
n
[
3
]
:
=
T
a
b
l
e
[
c
b
s
/
.
u
F
u
n
c
t
i
o
n
[
{
x
,
y
,
t
}
,
p
i
c
k
〚
i
,
2
〛
]
,
{
i
,
L
e
n
g
t
h
@
s
o
l
s
}
]
O
u
t
[
3
]
=
{
T
r
u
e
,
T
r
u
e
,
T
r
u
e
,
T
r
u
e
,
T
r
u
e
,
T
r
u
e
,
T
r
u
e
,
T
r
u
e
,
T
r
u
e
}
Use some other values for coefficients and exponents in the ansatz to obtain different solutions:
I
n
[
1
]
:
=
b
u
r
g
e
r
s
=
∂
t
u
[
x
,
t
]
+
u
[
x
,
t
]
∂
x
u
[
x
,
t
]
-
ν
∂
x
,
x
u
[
x
,
t
]
0
;
G
E
R
F
S
o
l
v
e
[
b
u
r
g
e
r
s
,
u
[
x
,
t
]
,
"
A
n
s
a
t
z
C
o
e
f
f
i
c
i
e
n
t
s
"
{
1
,
-
I
,
1
,
-
I
}
,
"
A
n
s
a
t
z
E
x
p
o
n
e
n
t
s
"
{
1
,
1
,
1
,
-
1
}
]
O
u
t
[
1
]
=
u
[
x
,
t
]
0
,
u
[
x
,
t
]
-
1
+
0
+
1
,
u
[
x
,
t
]
0
+
(
1
-
)
x
1
-
1
2
-
2
t
(
1
+
)
0
1
+
1
1
1
x
1
-
1
2
-
2
t
(
1
+
)
0
1
+
1
1
-
-
x
1
+
1
2
-
2
t
(
1
+
)
0
1
+
1
1
,
u
[
x
,
t
]
0
+
1
,
u
[
x
,
t
]
1
+
2
-
1
+
0
S
c
o
p
e
(
3
)
A
p
p
l
i
c
a
t
i
o
n
s
(
1
)
"
"